– [Voiceover] So we have a circle here and they specified some points for us. This little orangeish, or,

I guess, maroonish-red point right over here is the

center of the circle, and then this blue point

is a point that happens to sit on the circle. And so with that information,

I want you to pause the video and see if you can figure out

the equation for this circle. Alright, let’s work through this together. So let’s first think about

the center of the circle. And the center of the

circle is just going to be the coordinates of that point. So, the x-coordinate is negative one and then the y-coordinate is one. So center is negative one comma one. And now, let’s think about what the radius of the circle is. Well, the radius is going

to be the distance between the center and any point on the circle. So, for example, for example, this distance. The distance of that line. Let’s see I can do it thicker. A thicker version of that. This line, right over there. Something strange about my… Something strange about my pen tool. It’s making that very thin. Let me do it one more time. Okay, that’s better. (laughs) The distance of

that line right over there, that is going to be the radius. So how can we figure that out? Well, we can set up a right triangle and essentially use the distance formula which comes from the Pythagorean Theorem. To figure out the length of that line, so this is the radius, we could figure out a change in x. So, if we look at our

change in x right over here. Our change in x as we go from the center to this point. So this is our change in x. And then we could say that

this is our change in y. That right over there is our change in y. And so our change in x-squared plus our change in y-squared is going to be our radius squared. That comes straight out of

the Pythagorean Theorem. This is a right triangle. And so we can say that r-squared is going to be equal to our change in x-squared plus our change in y-squared. Plus our change in y-squared. Now, what is our change in x-squared? Or, what is our change in x going to be? Our change in x is going to be equal to, well, when we go from the radius to this point over here, our x goes from negative one to six. So you can view it as our ending x minus our starting x. So negative one minus negative, sorry, six minus negative one is equal to seven. So, let me… So, we have our change in x, this right over here, is equal to seven. If we viewed this as the start point and this as the end point, it would be negative seven, but we really care

about the absolute value in the change of x, and once you square it it all becomes a positive anyway. So our change in x right over here is going to be positive seven. And our change in y, well, we are starting at, we are starting at y is equal to one and we are going to y is

equal to negative four. So it would be negative four minus one which is equal to negative five. And so our change in y is negative five. You can view this distance right over here as the absolute value of our change in y, which of course would be

the absolute value of five. But once you square it, it doesn’t matter. The negative sign goes away. And so, this is going to

simplify to seven squared, change in x-squared, is 49. Change in y-squared,

negative five squared, is 25. So we get r-squared, we get r-squared is equal to 49 plus 25. So what’s 49 plus 25? Let’s see, that’s going

to be 54, or was it 74. r-squared is equal to 74. Did I do that right? Yep, 74. And so now we can write the

equation for the circle. The circle is going to be

all of the points that are, well, in fact, let me right all of the, so if r-squared is equal to 74, r is equal to the square-root of 74. And so the equation of

the circle is going to be all points x comma y that are this far away from the center. And so what are those points going to be? Well, the distance is going to be x minus the x-coordinate of the center. x minus negative one squared. Let me do that in a blue color. Minus negative one squared. Plus y minus, y minus the y-coordinate of the center. y minus one squared. Squared. Is equal, is going to

be equal to r-squared. Is going to be equal to the

length of the radius squared. Well, r-squared we already

know is going to be 74. 74. And then if we want to

simplify it a little bit, you subtract a negative,

this becomes a positive. So it simplifies to x plus one squared plus y minus one squared is equal to 74. Is equal to 74. And, we are all done.

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Thank you ππΎπ

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y is is squared? π²

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thank you so much, was so worried for my further maths GCSE!!!! This is so simple and makes perfect sense. Keep it up

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now I am confident doing A/s level math

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pls help me in my homework.. the question is: Reduce the equation of the circle to the general form.

given: x+2(y-x^2)=4+2y^2

what do i do first to make it into a general form? thanks in advance!

Shouldn't it be equal to 74^2

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sir i suggest you that please do not use red color for black background