4 thoughts on “Integration with partial fractions | AP Calculus BC | Khan Academy

  • June 15, 2018 at 7:31 pm
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    جميل جدا شكرا لك..

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  • June 15, 2018 at 8:57 pm
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    There's a much easier way to do this. Since the constants A&B have to be true for all values of x. And since the denominators are the same on both sides, just look at the numerators and set them as an equation.

    X – 5= a(x -1) + b(2x-3)

    First set x = 1, turning x -1 into 0, so the equation becomes

    1-5=b(2*1-3)
    Simplifying b equals 4. You can do the same thing, by picking x equals 3/2, cancelling out the b part of the equation, and solving for a

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  • February 10, 2019 at 11:41 pm
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    Helpful , Thank you

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